lets say the numbers are 1-9 do have to use all of them or can u not use some of them can u use 7 of the nine like lets say i use 1 2 3 4 7 8 9 can i do that or do they have to be in order like 1 2 3 4 5 6 7?
Ben there are only 7 different letters N,I,P,A,O,C,and R. Each letter stands for a different number, so every N is the same every time. Also there isn't a set of numbers you have to use just as long as when you multiply them every N is the same and every I and so forth. So no you don't have to use all the numbers 1-9 and you can't anyway.
i meen lets just say there are 7 numbers i think i got the answer but at the end one of the numbers is over 7 its 9 so i used 1 2 3 5 6 7 9 these are the nine numbers i used if it works with these nine numbers is it ok or does it have to be 1 2 3 4 5 6 7 and not 1 2 skip a few?
thats wat i thought yacova but htis is wat i always mess up with a prblem like this i always think its 1 but dont forget if n=5 and p=3 the 1's digit in 15 is 5 so n on the bottem is 5
N has to be a number that can be divided and can get one number that's the same as the last digit of the number right? Because let's say that N= 8... so then P = 6 so if 6 times 8 = 48 then N's last digit is 8 and 48 and 8 are the only numbers who can do that.
If you read my last note you could figure out now half the problem becuase P = 6 and so its ??6 times ?8! Aren't you happy I went on the blog. I hope you can understand what I said on my last one
36 comments:
Is guess and check the only strategy you can use?
If anyone needs help getting started try to figure out what I is there's a big clue in the letters because it spell NIP twice.
lets say the numbers are 1-9 do have to use all of them or can u not use some of them can u use 7 of the nine like lets say i use 1 2 3 4 7 8 9 can i do that or do they have to be in order like 1 2 3 4 5 6 7?
Ben there are only 7 different letters N,I,P,A,O,C,and R. Each letter stands for a different number, so every N is the same every time. Also there isn't a set of numbers you have to use just as long as when you multiply them every N is the same and every I and so forth. So no you don't have to use all the numbers 1-9 and you can't anyway.
i meen lets just say there are 7 numbers
i think i got the answer but at the end one of the numbers is over 7 its 9 so i used 1 2 3 5 6 7 9 these are the nine numbers i used
if it works with these nine numbers is it ok or does it have to be 1 2 3 4 5 6 7 and not 1 2 skip a few?
"I" must be 1 because Nip times "I" equals NIP. So the problem now is
N1P
X 1N
ANON
N1P
CORN
The letter "i" cannot be 0 because then it would have to be a 1-digit number.
i think "i" and "p" is one because pxn=n and ixn=n as well
wait nevrmind about i being one...sorry
n is either 5 or 6 because nxn = an so 6x6=36 and 5x5=25
thats wat i thought yacova but htis is wat i always mess up with a prblem like this i always think its 1 but dont forget if n=5 and p=3 the 1's digit in 15 is 5 so n on the bottem is 5
GREAT comments!
I does indeed have to be one since I x NIP = NIP.
I think that the only way to solve it is guess and check and maybe working backwards
no nevermind not backwards
i and n together has to be a two digit number because if i equals one then n and i would equal n but it doesnt it equals o
mrs cooper,
why did my other comment post as Jaren??
does the nip under anon mean to add them together because there is no sign
Yeah, you definitely have to use guess and check.
I think P=1 because because NxP=N.
p is not 1 what if u do n=5 and p =3 that works to i=1 because it says i times nip =nip just trust me
YES, N I P under A N O N does mean to add them together because this IS a two digit multiplication problem.
N has to be a number that can be divided and can get one number that's the same as the last digit of the number right? Because let's say that N= 8... so then P = 6 so if 6 times 8 = 48 then N's last digit is 8 and 48 and 8 are the only numbers who can do that.
If you read my last note you could figure out now half the problem becuase P = 6 and so its ??6 times ?8! Aren't you happy I went on the blog. I hope you can understand what I said on my last one
Wait so then if I equals 1 then the problem is now
N16
X 18
------
ANON
N16
-----
CORN
i MEST UP ON MY LAST NOTE, IT's supposed to be:
816
x 18
-----
A8O8
816
-----
COR8
nevermind ignore that comment... it's not right
i really hate these types of problems...
n+a added together can't equal more that 10 because then corn would have to have 5 digits
n+a added together can't equal more that 10 because then corn would have to have 5 digits
does p have to equal 1 so 1*n=n
n has to equal 5 because i am pretty sure that 5 is the only number that after its first 10 multiples, has the ones digit repeat itself. ex: 5*3=15
I agree with Ethan that A plus N can not sum up to 10 or anything more than that or else CORN would have 5 digits instead of 4.
N has to be a number that when is put to the power of 2(Multiplied by itself), equals a number with two digits(AN)
since tomorrow we disuss this ill just say wat i think is the answer n=5 p=3 i=1 a=2 o=6 r=9 c=7 is it right or wat
I like most all of your comments. They were very helpful!
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